Question

what changes will occur in raisin
and RBC when they are placed inside a hypotonic solution and why?​

Answer 1

Answer:

When both raisin and RBC placed inside a hypotonic solution both gains water and start swelling up .

It happens due to the less concentration of water inside the raisin and RBC as compared to the concentration of water outside region of the raisin and RBC.

Explanation:

MARKS AS BRAINLIEST AS WELL AS FOLLOW ME FOR MORE SUCH TYPES OF ANS.

Answer 2

When raisin and RBC are placed inside a hypotonic solution, water enters them by the process of endosmosis. This leads to the swelling up and finally bursting of cell.

• It is because hypotonic solution refers to a solution having a lower concentration of solute( and so a higher amount of water) and so the solute concentration inside the RBC or raisin is greater than the solution( and water content is less). As a result of this, water enters into the cells to maintain osmolarity.
• Water enters into the raisin and RBC, thereby leading to a swelled up structure.
• The RBC does not have any cell wall to maintain rigidity so continuous entry of water leads to hemolysis of RBC( rupture or destruction of cells).