Question

What concentration of nitrogen should
be present in a glass of water at room
temperature? Assume a temperature of 25°C
a total pressure of 1 atmosphere and mole
fraction of nitrogen in air of 0.78.
[Kh for nitrogen = 8.42 x 10 M/mm Hg)
(3/5, AI 2009)​

Answer 1

Answer:

Explanation:

PN2= 1 atmosphere

PN2=KH×N2

By Henry's law

xN2=PN2KH=18.42×10−7

xN2=n(N2)n(N2)+n(H2O)

xN2=n(N2)n(H2O)

n(N2)=xN2.n(H2O)

nN2=xN2.100018

⇒18.42×10−7×55.5

⇒6.59×107 moles

Hence concentration of nitrogen =6.59×107molL−1