what constant torque should be applied to a disc of mass 16 kg and 0.5 m diameter so that it acquires and angular velocity of 4 Pi Radian/s in 8 seconds? the disk is initially at rest and rotates about an Axis through the centre of desk and in a plane perpendicular to the disc.
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torque =force×perpendicular distance
1 kgf =1 kg
1kgf=10 newton
so,16kg= 16×10=160newton
distance=o.5 m
0.5×160=80 newton meter
1 kgf =1 kg
1kgf=10 newton
so,16kg= 16×10=160newton
distance=o.5 m
0.5×160=80 newton meter
abhishek517:
buddy 1 kgf = 9.8 N
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