Question

What could be the possible ‘one's digits of the square root of each of the following
numbers?
a) 1801 b) 856 c)10087
if u answer I will mark u brainiest and pls show ur work to thank you

Answer 1

Answer:

In actuality, all three of these numbers are not perfect squares, so their square roots won't be integers.

However, assuming these numbers to be perfect squares,

1801 has one's digit as ONE, so it's square root will theoretically have one's digit as ONE or NINE.

856 has one's digit as SIX. so it's square root will theoretically have one's digit as FOUR or SIX.

10087 has one's digit as SEVEN, but no single digit integer has a perfect square ending with 7.

The actual square roots of these numbers are:

a) 1801 : 42.438

b) 856: 29.257

c) 10087 : 100.434

Do mark as brainliest if it helped!