what current will flow in a 120 volt circuit containing 3 resisitances of 1.5ohms, 3.0 ohms, and 4.5 ohms connected in parallel?
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here equivalent resistance of given parallel connection
1/r = 1/r1+1/r2+1/r3
1/r = 1/1.5+1/3+1/4.5
1/r = (6+3+9)/4.5
1/r = 18/9
r= 9/18 =0.5Ohm
so I =V/r = 120/0.5 = 240A
1/r = 1/r1+1/r2+1/r3
1/r = 1/1.5+1/3+1/4.5
1/r = (6+3+9)/4.5
1/r = 18/9
r= 9/18 =0.5Ohm
so I =V/r = 120/0.5 = 240A
shadrack20:
I have a small question how did you get the 6 3 and 9
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here is the answer......
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