Question

What current will the 6V battery push through the 1kΩ resistor?

Answer 1

Answer:

6 mA

Explanation:

According to Ohm's Law,

V = I*R

We have V= 6 V, R = 1000 ohms

hence,

I = V/ R

I = 6/1000

I = 6 mili amperes

I = 6 mA

Answer 2

Answer:

here,

V = 6V

R = 1 kΩ = 1000 Ω

I = ?

by ohm's law,

V = iR

so,.

I = V/R

= 6/1000 A

= 6 × 10^-3 A

= 6 milli ampere.

hence the current is 6 milliampere.