Question

What distance must separate two charges of + 5.6×10-4C and -6.3×10-4 C in order to have an electric potential energy with a magnitude of 5.0 J in the system of the two charges?​

Answer 1

$\huge\underline\mathfrak{\pink{Solution}}$

$\text{ \red{The magnitude of the electric potiential energy }}$

$\text\red{Ep of a system of two charges q1 and q2 separated by a distance r is given by}}$

Ep = k | q1 | | q2 | / r

$\sf \red{Solve\: for \:r.}$

r = k q1 q2 / Ep = 9.00×109×5.6×10-4×6.3×10-4 / 5.0 = 6.35×102 m

Answer 2

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