Question

What do you know about chords that are equidistant from the center of the circle?

Answer 1

if chords are equidistant from the centre of the circle that means they are equal and also they subtend equal angle to the centre of that circle

Answer 2

To Prove: AB = CD

Construction: Join OA and OC.

Proof:

OL ⊥ AB

⇒AL = BL [ Since, the ⊥cular from the centre of a circle to a chord bisects the chord ]

and, OM ⊥ CD

⇒ CM = DM [ Since, the ⊥cular from the centre of a circle to a chord bisects the chord

=> OA=OC (Common hypotenuse)

Therefore..♢ALO ~= ♢CMO( SSS rule)

NOW....AL=CM (C.P.C.T)

AND 2AL=2 CM

Therefore..AB=CD (Hence, Proved)


I hope it is helped you