What does (1+i)⋅(6−2i)4i equal?
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(1+i).(6-2i)4i=[6-2i+6i-2i^2]4i
=[6+4i-2(-1)]4i
=[8+4i]4i
=(32i+16i^2)
=16(2i-1)
therefore,the answer is 16(2i-1).
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