What does 1M of sulfuric acid plus 2g of
aluminum give? In balanced form.
Answers
Answer:
Balanced Equation:
2
Al(s)
+
3
H
2
SO
4
(
aq
)
→
Al
2
(
SO
4
)
3
(
aq
)
+
3
H
2
(
g
)
Explanation:
Al(s) + H
2
SO
4
(
aq
)
→
Al
2
(
SO
4
)
3
(
aq
)
+
H
2
(
g
)
Start with the polyatomic sulfate ion,
SO
4
. There is one sulfate ion on the left-hand side and there are three on the right-hand side. Place a coefficient of
3
in front of
H
2
SO
4
.
Al(s)
+
3
H
2
SO
4
(
aq
)
→
Al
2
(
SO
4
)
3
(
aq
)
+
H
2
(
g
)
There are now six hydrogen atoms on the left-hand side and two hydrogen atoms on the right-hand side. Place a coefficient of
3
in front of
H
2
.
Al(s)
+
3
H
2
SO
4
(
aq
)
→
Al
2
(
SO
4
)
3
(
aq
)
+
3
H
2
(
g
)
There is one aluminum atom on the left-hand side and two on the right-hand side. Place a coefficient of
2
in front of
Al
on the left-hand side.
2
Al(s)
+
3
H
2
SO
4
(
aq
)
→
Al
2
(
SO
4
)
3
(
aq
)
+
3
H
2
(
g
)
Number of atoms of each element on each side:
Left-hand side: 2 Al, 6 H, 3 S, 12 O
Right-hand side: 2 Al, 6 H, 3 S, 12 O
Both sides have the same number of atoms of each element and the equation is therefore balanced.