Question

what force is required to increase the velocity of 6 kg mass from 8m/s to 28m/s in 5 second

Answer 1

Answer:

24 N

Explanation:

Given,

Initial velocity of the object (u) = 8 m/s

Final velocity of the object (v) = 28 m/s  

Mass of the object (m) = 6 kg

We need acceleration produced to find force

i.e, Acceleration of the object = $\frac{v-u}{t}$ $= \frac{28-8}{5}$ = $4m/s^{2}$

Force = mass * acceleration

Force = 6 * 4 = 24 N

Therefore, force required is 24 N

Thank you

Answer 2

Answer:

The force required to increase the velocity of 6 kg mass from 8m/s to 28m/s in 5 s is 24 N.

Explanation:

Given mass m = 6 kg

Given initial velocity u = 8 m/s

Given final velocity v = 28 m/s

Given time interval t = 5 s

We know that acceleration a = $\frac{v-u}{t}$

                                                = $\frac{28-8}{5}$ = $4 m/s^{2}$

Force = mass × acceleration

         = 6 × 4 = 24 N

Therefore the force required to increase the velocity of 6 kg mass from 8m/s to 28m/s in 5 s is 24 N.