What force is required to stretch a steel wire 1mm2
in cross-section to
increase its length 20%. Given Y= 2x1011 Nm-2
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Question:-
What force is required to stretch a steel wire 1mm2
in cross-section to
increase its length 20%. Given Y= 2x1011 Nm-2
Answer:-
Given that,
Young modulus Y=1.26×10
12
dyne/cm
Area A=1cm
2
As the length of the wire is doubled, the change in length is equal to its
original length.
If L is the original length
Then, Δl=l
We know that,
Y=
A×ΔL
F×L
F=Y×A
F=0.126×10
12
×1×10
−4
F=1.2×10
7
N
Hence, the force is 1.2×10
7
N
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