what force should be applied on a 10 kg body so that it moves
down in vacuum with an acceleration of 3 m/s^2?(Take g=9.8m/s^2)
Answers
Answered by
14
Answer:
-68N
Explanation:
since the body is moving downwards the acceleration of the body becomes(a-g) hence F=ma =>F=m(a-g) therefore F=10(3-9.8)=-68N
Answered by
3
Answer:
mass = 10 kg
acc = 3 m/s²
force = mass × acceleration
= 10 × 3
= 30 N
Explanation:
note: the force should be continuous not for a moment
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