Physics, asked by tayraven, 1 year ago

What force should be applied on the wedge so that block over it does not move? (All surfaces are smooth)
(1) F = (M + m) g cot ∅
(3) F = (M + m) g sin ∅
(2) F = (M + m) g tan ∅
(4) F = (M + m) g cos∅​

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Answers

Answered by JinKazama1
76

Answer:

(3) F=(M+m)gtan(\theta)

Explanation:

1) We know,

Acceleration of system,

F=(m+M)a\\ \\=>a=\frac{F}{m+M}

2) Then,

Applying pseudo force on m,= ma

Force Balance for 'm' to be at rest.

N sin(\theta)=ma

Ncos(\theta)=mg

Dividing above equations,

we get,

a=gtan(\theta)\\ \\=>\frac{F}{m+M}= gtan(\theta)\\ \\=>F=(m+M)gtan(\theta)

Hence, option (2) is correct option.

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Answered by mssampath13850
14

Answer:

for answer view the picture

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