Question

What fraction of a wooden raft of density 0.8 gcm¯³ will be inside the sea water of density 1.2 gcm¯³?

Answer 1

Answer:

fraction is $\frac{3}{2}$

Explanation:

Archimedes principal state that weight of liquid displayed by body is equal to weight of body under liquid

since weight of wooden raft is vρg, where v is volume of wooden raft, ρ is density of raft and g is acceleration due to gravity.

weight of liquid displayed is v'σg, where v' is volume of liquid displayed, σ is density of liquid and is acceleration due to gravity.

from law,

weight of raft under water=weight of liquid displayed

vρg=v'σg (g cancelled eachother)

vρ=v'σ

v0.8=v'1.2

$\frac{v}{v'}$=$\frac{1.2}{0.8}$

$\binom{v}{v'}{=V}$

V=$\frac{12}{8}$

V=$\frac{3}{2}$

Answer 2

Answer:

V = 3 / 2

Explanation:

Archimedes principal state that weight of liquid displayed by body is equal to weight of body under liquid

since weight of wooden raft is vρg, where v is volume of wooden raft, ρ is density of raft and g is acceleration due to gravity.

weight of liquid displayed is v'σg, where v' is volume of liquid displayed, σ is density of liquid and is acceleration due to gravity.

from law,

weight of raft under water-weight of liquid displayed

vpg = v'o g (g cancelled each other)

v p = v ' o

v / v2 = 1 . 2 / 0 . 8

v / v 2 = V

V = 1 2 / 8

V = 3 / 2

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