Question

What happens to h at the center of a circular coil when radius of coil is halved and current flowing through the coil is increased 2 times?

Answer 1

Answer:

At the center of a current carrying coil, the magnetic field intensity is directly proportional to the current and inversely proportional to the radius of the coil. So, if the current is doubled and radius is halved, then the value of B increases by 4 times the initial value.

Answer 2

Explanation:

What happens to h at the center of a circular coil when radius of coil is halved and current flowing through the coil is increased 2 times?