Question

what happens to the current if the area of cross section of wire is halved ? ( class 10 physics chapter electricity ​

Answer 1

Answer:

The new current would be 1/2 the initial one

Explanation:

  R = δl /A

V /I = δl /A

$I_{1}$ = VA /δl

The new current be $I_{2}$

$I_{2}$ = 1VA /2δl

   = 1/2 $I_{1}$