what happens to the kinetic energy when the mass of the body is doubled but velocity is reduced of
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K.E=1/2mv^2
K.E is directly proportional to mass and square of velocity
given that M2=2×M1,V2=1/2×V1
so,K1/K2 =M1/M2 ×(V1/V2)^2
K1/K2=m/2m×(2v/v)^2
It gives K1/K2 =2
K2=K1/2
Kinetic energy becomes half of its initial energy..
K.E is directly proportional to mass and square of velocity
given that M2=2×M1,V2=1/2×V1
so,K1/K2 =M1/M2 ×(V1/V2)^2
K1/K2=m/2m×(2v/v)^2
It gives K1/K2 =2
K2=K1/2
Kinetic energy becomes half of its initial energy..
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Hey!!!
I hope this answer will help you.
I hope this answer will help you.
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