What happens to the resistance of a conductor whose area is doubled?
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let the resistance of wire = r
resistivity of wire = R
area of cross - section = A
length of wire = l
resistance of wire , r = R×A/l -----(1)
when the area is doubled the new area is = 2A
let the resistance = r1 = R×2A/l -------(2)
divide eq. (2) by (1)
r/r1 = (R×A/l)/(R×2A/l)
r/r1 = 1/2
r1 = 2r
therefore , the resistance of wire became double
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