Question

what happens to the time period of a simple pendulum when it's length is increased to four times its value?

Answer 1

Let length be a

a1 = a
a2 = 4a

T = 2π √a/g

T1/T2 = √a1/a2 = 1/2

T2 = 2 T1

So, time period is doubled

Answer 2

Answer:

time period will be doubled

Explanation:

T= 2π√l/g

T is directly proportional to √l

if L becomes 4L then T will become double