WHAT HAPPENS VINEGAR REACTS WITH NaOH
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Explanation:
When Ethanoic acid present in vinegar reacts with sodium hydroxide or caustic soda then sodium acetate or sodium ethanotate and water is formed.
Chemical equation :-
- CH3COOH + NaOH -> CH3COONa + H2O
- This is the example of Neutralisation reaction.
Additional information :-
- CH3COOH is a weak acid and NaOH is a strong base.
- The reaction between an acid and a base to form salt and water is called Neutralisation reaction.
- CH3COOH = Ethanoic acid or Acetic acid
- CH3COONa = Sodium ethanotate or sodium acetate
- NaOH = sodium hydroxide or caustic soda
- H2O = water
Molar mass of :-
C2H4O2 or CH3COOH :-
» 12×2 + 1×4 + 16×2
» 24 + 4 + 32
- » 60 g/mol
CH3COONa or C2H3O2Na :-
» 12×2 + 1×3 + 16×2 + 23
» 24 + 3 + 32 + 23
- » 82 g/mol
NaOH :-
» 23 + 16 + 1
- » 40 g/mol
H2O :-
» 1×2 + 16
- » 18 g/mol
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Answer:
sodium ethnotate and water is formed .
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