Question

what ia 4-3[4-2(6-3)]÷2 equal

Answer 1

I do not know which is the correct question, so i do it in two ways:

$\frac{4 - 3 [ 4 - 2 ( 6 - 3 ) ]} {2} \\ \\ = \frac{4-3[3-2(3)]}{2} \\ \\ = \frac{4-3[4-6]}{2} \\ \\ = \frac{4-3[-2]}{2} \\ \\ = \frac{4+6}{2} \\ \\ = \frac{10}{2} \\ \\ 5$
=================
$\\ 4 - \frac{3*[4-2(6-3)]}{2} \\ \\ 4 - \frac{3*[4-2(3)}{2} \\ \\ 4 - \frac{3*[4-6]}{2} \\ \\ 4 - \frac{3(-2)}{2} \\ \\ 4 - \frac{-6}{2} \\ \\ 4 - (-3) \\ \\ 4 + 3 = 7$

Answer 2

$4-3[4-2(6-3)]:2=4-3(4-2\cdot3):2=4-3(4-6):2\\\\=4-3\cdot(-2):2=4+6:2=4+3=\fbox7$