what ia 4-3[4-2(6-3)]÷2 equal
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I do not know which is the correct question, so i do it in two ways:
![\frac{4 - 3 [ 4 - 2 ( 6 - 3 ) ]} {2} \\ \\ = \frac{4-3[3-2(3)]}{2} \\ \\ = \frac{4-3[4-6]}{2} \\ \\ = \frac{4-3[-2]}{2} \\ \\ = \frac{4+6}{2} \\ \\ = \frac{10}{2} \\ \\ 5 \\ \\](https://tex.z-dn.net/?f=%5Cfrac%7B4+-+3+%5B+4+-+2+%28+6+-+3+%29+%5D%7D+%7B2%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B4-3%5B3-2%283%29%5D%7D%7B2%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B4-3%5B4-6%5D%7D%7B2%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B4-3%5B-2%5D%7D%7B2%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B4%2B6%7D%7B2%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B10%7D%7B2%7D+%5C%5C+%5C%5C+5+%5C%5C+%5C%5C+ "\frac{4 - 3 [ 4 - 2 ( 6 - 3 ) ]} {2} \\ \\ = \frac{4-3[3-2(3)]}{2} \\ \\ = \frac{4-3[4-6]}{2} \\ \\ = \frac{4-3[-2]}{2} \\ \\ = \frac{4+6}{2} \\ \\ = \frac{10}{2} \\ \\ 5 \\ \\")
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![\\ 4 - \frac{3*[4-2(6-3)]}{2} \\ \\ 4 - \frac{3*[4-2(3)}{2} \\ \\ 4 - \frac{3*[4-6]}{2} \\ \\ 4 - \frac{3(-2)}{2} \\ \\ 4 - \frac{-6}{2} \\ \\ 4 - (-3) \\ \\ 4 + 3 = 7 \\](https://tex.z-dn.net/?f=%5C%5C+4+-+%5Cfrac%7B3%2A%5B4-2%286-3%29%5D%7D%7B2%7D+%5C%5C+%5C%5C+4+-+%5Cfrac%7B3%2A%5B4-2%283%29%7D%7B2%7D+%5C%5C+%5C%5C+4+-+%5Cfrac%7B3%2A%5B4-6%5D%7D%7B2%7D+%5C%5C+%5C%5C+4+-+%5Cfrac%7B3%28-2%29%7D%7B2%7D+%5C%5C+%5C%5C+4+-+%5Cfrac%7B-6%7D%7B2%7D+%5C%5C+%5C%5C+4+-+%28-3%29+%5C%5C+%5C%5C+4+%2B+3+%3D+7+%5C%5C+ "\\ 4 - \frac{3*[4-2(6-3)]}{2} \\ \\ 4 - \frac{3*[4-2(3)}{2} \\ \\ 4 - \frac{3*[4-6]}{2} \\ \\ 4 - \frac{3(-2)}{2} \\ \\ 4 - \frac{-6}{2} \\ \\ 4 - (-3) \\ \\ 4 + 3 = 7 \\")
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AvmnuSng:
that's nice, but would u pls. make every =sign in new line and replace the ':' with the actual division sign as used in question
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