What if boy and the girl pull heavy object at the same time in opposite direction with 20 units and 5 units of force respectively.w&at will be the net force on the object? will the object move?to what direction will move?
Answers
Explanation:
The answer provided by Mr. Xu is essentially correct in theory but is incomplete. There is a subtle and hidden physical consideration in this question that his answers ignores. The WEIGHT (w) of the object will actually make a DIFFERENCE in the determination of the NET FORCE.
Case I: the two forces are in the same direction, along (+ x). The NET force is 20 N along (+ x).
Case II: The two forces are in OPPOSITE direction along x-axis. The NET force is ZERO.
Case III: the two forces are in the same direction along (- x). The NET force is (- 20 N).
Case IV: The two forces are in the (+ y) direction. The NET force is: [(20 - w) N].
Case V: The two forces are in the (- y) direction. The NET force is: [(20 + w) N].
Case VI: one force is in the (+ y) and the other is in (- y). The Net force is (w).
In all other cases, we must break down the two 10 N forces into (x & y) components and find SIGMA FORCE, as Mr. Xu suggests.
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Answer:
net force is 15 , object will move towards the boy
Explanation:
since the forces are in opposite directions the net force will be difference between the magnitudes of the forces , so we will just subtract the lower force from higher and the object should move on the side where it is experiencing more force.