Question

What In the given figure, equilateral ΔABD and ΔACE are drawn on the sides of a ΔABC.
Prove that CD = BE.

Answer 1

CD=BE

Step-by-step explanation:

<A=<A (common angle, given)

side AE = side AD (equilateral triangle )

side CE = side BD (equilateral triangle )

Therefore CD=BE (CPCT)

Corresponding Part of Congruent Triangle