what is 1+2+3+4+5+6+7+8+.............upto infinity
Meghasyam:
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Hey
Is in in the form of AP .
where ,
a = 1
d = 1
let number of terms be n .
So ,
Sn = n / 2 [ 2 + ( n - 1 ) 1 ]
= n / 2 [ 2 + n - 1 ]
= n / 2 [ 1 + n ]
= n² + n / 2 .
But there is a mathematician , named Ramanujan .
He gave the concept that
1 + 2 + 3 + 4 + .........infinity
= -1 / 12
prove of this is a bit lendy .
if u want then do spread words in comment section .
thanks ^_^
Is in in the form of AP .
where ,
a = 1
d = 1
let number of terms be n .
So ,
Sn = n / 2 [ 2 + ( n - 1 ) 1 ]
= n / 2 [ 2 + n - 1 ]
= n / 2 [ 1 + n ]
= n² + n / 2 .
But there is a mathematician , named Ramanujan .
He gave the concept that
1 + 2 + 3 + 4 + .........infinity
= -1 / 12
prove of this is a bit lendy .
if u want then do spread words in comment section .
thanks ^_^
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