Question

What is ∫16sin2xcos2xdx?

Answer 1

★Heya★

Let's make this function in simpler form

Sin2x × Cos2x =

1/2{Sin ( 2x + 2x ) + Sin ( 2x - 2x ) }

=

1/2 { Sin ( 4x ) }

=>

So, it's integration is

-8 Cos (4x) / 4

=

-2 Cos (4x)