Question

what is 30th term of an ap1,2,3..

Answer 1

heya,
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a = 1
d = 2 - 1 = 1
n = 30
now,
a + ( n - 1 ) d = an
an = 1 + ( 30 - 1 ) 1 
     = 1 + 29
     = 30
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hope this helped u,
cheers

Answer 2

$\huge{\mathfrak{\underline {\underline{\red{Answer :-}}}}}$

30th term is 30

$\large{\mathrm{\underline{\gray{Given :-}}}}$

A.P :- 1, 2, 3

First term(a) = 1

${\sf{Common \:\: difference(d) \: = \: a_{2} - a_{1}}}$

Common difference = 2 - 1 = 1

$\large{\mathrm{\underline{\gray{To \: Find :-}}}}$

30th term

$\large{\mathrm{\underline{\gray{Solution :-}}}}$

First Method :-

an = a + 29d

__________________[Put Values]

${a_{30} = 1 + 29(1)}$

${a_{30} = 1 + 29}$

${a_{30} = 30}$

Second Method :-

Using Formula

$\huge{\boxed{\boxed{Tn \: = \: a + (n - 1)d}}}$

__________________[Put Values]

$\bf{a_{30} \: = \: 1 + (30 - 1)1}$

$\bf{a_{30} \: = \: 1 + 29(1)}$

$\bf{a_{30} \: = \: 1 + 29}$

$\bf{a_{30} \: = \: 30}$

$\huge{\boxed{\boxed{\blue{a_{30} \: = \: 30}}}}$