what is a balancing equation and give examples
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Answered by
1
it is nothing but to check the amt of product and reactant r equal
for eg the q uest is
mg +o2--->2mgo
but it is skeleton equation
but after adding 2 to the element mg it will lead to a chemical reation
2mg+o2--->2mgo
and these rules r known as stocheometry rules
for eg the q uest is
mg +o2--->2mgo
but it is skeleton equation
but after adding 2 to the element mg it will lead to a chemical reation
2mg+o2--->2mgo
and these rules r known as stocheometry rules
Answered by
0
The process of making the number of different types of atoms equal on both the sides (reactants and products) of an equation is called balancing of equation.
Ex-
When hydrogen burns in oxygen to form water. This reaction can be written in an equation form as:
H2 +O2 = H2O
In this reaction H2 and O2 are reactants whereas H2O is the product. Let us count the number of hydrogen atoms and oxygen atoms in reactants and product.
In reac. In pro.
No. of H atoms: 2 2
No. of O atoms: 2 1
The number of hydrogen atoms is equal on both sides(2 each), but the number of oxygen atoms is unequal. There are 2 oxygen atoms on the left side but only 1 oxygen atom on the right side. To have 2 oxygen atoms on the right side, we multiply H2O by 2 and write 2H2O, so that:
H2 +O2 = 2H2O
Let us count the number of various atoms on both the sides again:
In reac. In pro.
No. of H atoms: 2 4
No. of O atoms: 2 2
Though the number of oxygen atoms has become equal(2 on both sides), but the number of hydrogen atoms has now become unequal. There are 2 hydrogen atoms on the left sides but 4 hydrogen atoms on the right side. To have 4 hydrogen atoms on the left side, we multiply H2 by 2 and write 2H2, so that:
2H2 +O2 = 2H2O
Let us count the number of various atoms on both the sides once again.
In reac. In pro.
No. of H atoms: 4 4
No. of O atoms: 2 2
This chemical equation contains an equal number of atoms of hydrogen and oxygen on both the sides, so this is a balanced equation.
Ex-
When hydrogen burns in oxygen to form water. This reaction can be written in an equation form as:
H2 +O2 = H2O
In this reaction H2 and O2 are reactants whereas H2O is the product. Let us count the number of hydrogen atoms and oxygen atoms in reactants and product.
In reac. In pro.
No. of H atoms: 2 2
No. of O atoms: 2 1
The number of hydrogen atoms is equal on both sides(2 each), but the number of oxygen atoms is unequal. There are 2 oxygen atoms on the left side but only 1 oxygen atom on the right side. To have 2 oxygen atoms on the right side, we multiply H2O by 2 and write 2H2O, so that:
H2 +O2 = 2H2O
Let us count the number of various atoms on both the sides again:
In reac. In pro.
No. of H atoms: 2 4
No. of O atoms: 2 2
Though the number of oxygen atoms has become equal(2 on both sides), but the number of hydrogen atoms has now become unequal. There are 2 hydrogen atoms on the left sides but 4 hydrogen atoms on the right side. To have 4 hydrogen atoms on the left side, we multiply H2 by 2 and write 2H2, so that:
2H2 +O2 = 2H2O
Let us count the number of various atoms on both the sides once again.
In reac. In pro.
No. of H atoms: 4 4
No. of O atoms: 2 2
This chemical equation contains an equal number of atoms of hydrogen and oxygen on both the sides, so this is a balanced equation.
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