Math, asked by anitamarneanita4903, 10 months ago

What is a HCF of 66,110,121

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Answered by laksh200315903
0

Answer:

Step-by-step explanation: hcf of 66,110 and121 by euclids devision lemma is as follows:

first we find hcf of66 and 110

110=66×1+44

66=44×1+22

44=22×2+0

so hcf of 110 and 66 is 22

lets verify it for 121

121=22×5+11

22=11×2+0

therefor hcf of 66,110 and 121 is 11

Answered by Anonymous
0

here is your answer mate.

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