What is a HCF of 66,110,121
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Step-by-step explanation: hcf of 66,110 and121 by euclids devision lemma is as follows:
first we find hcf of66 and 110
110=66×1+44
66=44×1+22
44=22×2+0
so hcf of 110 and 66 is 22
lets verify it for 121
121=22×5+11
22=11×2+0
therefor hcf of 66,110 and 121 is 11
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here is your answer mate.
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