Question

what is (a) highest (b) lowest resistance that can be secured by combining by four coils of resistance 4ohm, 8ohm, 12ohm, 24ohm?​

Answer 1

(a)Highest; Series

R=R1+R2+R3+R4

  =4+8+12+24=48 ohm

(b)Lowest; Parallel

1/R= 1/R1+1/R2+1/R3+1/R4

    = 1/4+1/8+1/12+1/24

    =  (6+3+2+1)/24

    =  35/24  

R= 24/35=0.685 or 0.67

Took me a lot of time to answer and I even cancelled the page so please mark as brainliest. Oh man my hand  hurts