what is an equation of a line that passesthrough the points (1,6) and (2,1) ?
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Answered by
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50crisaiah:
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Answered by
71
Hey there!
Answer:
let x1 = 1
x2 = 2
y1 = 6
y2 = 1
Now slope ( m ) :
= y2 - y1/x2- x1
= 1 - 6 / 2 - 1
= -5 / 1
= - 5
Now Equation :
y - y1 = m ( x - x1 )
y - 6 = - 5 ( x - 1 )
y - 6 = -5x + 5
y + 5x = 5 + 6
5x + y = 11
5x + y - 11 = 0
Which is required equation
Answer:
let x1 = 1
x2 = 2
y1 = 6
y2 = 1
Now slope ( m ) :
= y2 - y1/x2- x1
= 1 - 6 / 2 - 1
= -5 / 1
= - 5
Now Equation :
y - y1 = m ( x - x1 )
y - 6 = - 5 ( x - 1 )
y - 6 = -5x + 5
y + 5x = 5 + 6
5x + y = 11
5x + y - 11 = 0
Which is required equation
is it correct?
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