what is angle measure of angle cba
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Option.C=60°
In ∆ACD , Angle C= 80° ==> Angle opposite to equal sides are equal.
Then, In ∆ACD , Angles A+C+D=180 =>Angle sum property
Hence, 180-(80+80) = Angle A
CAD (or x)= 20
Now , in ∆ABC , we know that, x=20
then in ∆ABD , Angles A+B+D=180 ==>angle sum of triangle
But , A= BAC + CAD
A= 40
Then , A+B+D = 180
B = 180-(80+40)
B= 180-120
B = 60°
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