Math, asked by SoulStealer7284, 1 year ago

What is answer of 36/136*100?find with caluculation

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Answered by afreen786n
113
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HEY BUDDY HERE IS UR ANSWER


 \binom{36}{136}  \times 100 \\    =  \binom{450}{17} \\ = 26.47058




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BY AFREEN NAAZ
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Answered by payalchatterje
2

Answer:

Required answer is  64\frac{2}{17}

Step-by-step explanation:

Here given term is

 \frac{36}{136 } \times 100

We want to simplify it.

First we are breaking 36,136 and 100 into prime numbers.

36 = 2 \times 2 \times 3 \times 3 \\ 136 = 2 \times 2 \times 2 \times 17 \\ 100 = 2 \times 2 \times 5 \times 5

Now,

 \frac{36}{136 } \times 100  \\ =  \frac{(2 \times 2 \times 3 \times 3)(2 \times 2 \times 5 \times 5)}{(2 \times 2 \times 2 \times 17)}  \\     =  \frac{450}{17}=64\frac{2}{17}

This is a problem of Algebra.

Some important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

{a}^{2}  -  {b}^{2}  = (a + b)(a - b)\\{a}^{2}  +  {b}^{2}  =  {(a + b)}^{2}  - 2ab\\{a}^{2}  +  {b}^{2}  =  {(a - b)}^{2}  + 2ab\\{a}^{3}  -  {b}^{3}  = (a  -  b)( {a}^{2}   +  ab +  {b}^{2} )\\{a}^{3}   +   {b}^{3}  = (a + b)( {a}^{2}    -   ab +  {b}^{2} )

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