Question

what is area of an isosceles triangle whose base is 18cm and one of its equal sides is 15cm?​

Answer 1

AREA=108cm^2.

area of triangle= root over (s-a)(s-b)(s-c) .first we find s . s=a+b+c/2 ok .so,s=18+15+15/2=24.now area of triangle=rootover 24(24-18)(24-15)(24-15)=rootover 24(6)(9)(9) now we find the prime factor so, the prime factor is rootover 2×2×2×3×2×3×3×3×3×3=now we make the pair bcoz it is in the root ok.so,2×2×3×3×3=4×9×3=108. so, the area of triangle is 108m^2 .

hope it's helps...

Answer 2

Use Heron's Formula

Step-by-step explanation:

• The easiest is probably to use Heron’s Theorem.
• A = √(s(s-a)(s-b)(s-c)). where A is the area and S is the semiperimeter or half the sum of the sides.
• The lowercase a, b, and c are the sides.
• We add up the sides and divide by two to get
• S = 15 + 15 + 18 = 48. 48/2 = 24.
• Then we plug s and the values for the sides into the formula.
• A = √(24(24–18)(24–15)(24–15))
• It comes out to $108\ cm^2$.