Computer Science, asked by chintasurya79, 10 months ago

What is Big-endian order of 78563412h?
(first column represents the address)
a) | 0003 | 78 | b) | 0003 / 56
0002 : 56
0002 78
0001
0000
0001
0000
0003 12
0002 | 34
0001 56
0000 78
d) | 0003 / 34
| 0002 12
0001 178
| 0000 56​

Answers

Answered by nanshisingh123
49

Answer:

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Answered by sadiaanam
0

Answer: The correct option is :

b) | 0003 / 56

0002 78

0001 56

0000 34

Explanation:

Big-endian and little-endian are two different ways of storing multi-byte data in computer memory. In big-endian order, the most significant byte (MSB) is stored at the lowest memory address, while the least significant byte (LSB) is stored at the highest memory address.

In this case, we are given the hexadecimal value 78563412h, which represents a 32-bit unsigned integer. To convert this into big-endian order, we need to swap the bytes in the hexadecimal representation.

Starting from the MSB, the bytes are:

78 56 34 12

In big-endian order, the MSB 78 will be stored at the lowest memory address and the LSB 12 will be stored at the highest memory address.

Therefore, the correct option would be:

b) | 0003 / 56

0002 78

0001 56

0000 34

Learn more about big-endian order :
https://brainly.in/question/35761475

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