Math, asked by bindumolsebastian, 10 months ago

What is

bx/a+ay/b=a^2+b^2

x+y=2ab




Please answer fast.

The first correct answer will be the brainiest answer

Answers

Answered by dev294joshi
0

Answer:

bx/a +ay/b =a^2+b^2

taking LCM

(b^2x + a^2y)/ab = (a^2 + b^2)

multiplying ab on both sides

b^2x + a^2y = (a^2 + b^2)(ab) --- 1

in other eq.

x + y = 2ab

so, ab = (x+y)/2 --- 2

Substituting 2 in 1

b^2x + a^2y = (a^2 + b^2)(x + y)/2

multiplying 2 on other side

2b^2x + 2a^2y = a^2x + a^2y + b^2x + b^2y

b^2x + a^2y = a^2x + b^2y

b^2x - a^2x = b^2y - a^2y

x(b^2 - a^2) = y(b^2 - a^2)

cancelling on both sides

x=y

Hope it helps :)

Answered by 16RE78
0

Answer:

bx/a +ay/b =a^2+b^2

taking LCM

(b^2x + a^2y)/ab = (a^2 + b^2)

multiplying ab on both sides

b^2x + a^2y = (a^2 + b^2)(ab) --- 1

in other eq.

x + y = 2ab

so, ab = (x+y)/2 --- 2

Substituting 2 in 1

b^2x + a^2y = (a^2 + b^2)(x + y)/2

multiplying 2 on other side

2b^2x + 2a^2y = a^2x + a^2y + b^2x + b^2y

b^2x + a^2y = a^2x + b^2y

b^2x - a^2x = b^2y - a^2y

x(b^2 - a^2) = y(b^2 - a^2)

cancelling on both sides

x=y

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