Question

What is centripetal acceleration of an object in uniform circular motion at the end of a 1m rope making 1 revolution per sec:39 m/s2 inward39 m/s2 outward39 m/s2 tangentially1 m/s2 inward

Answer 1

39m/s2inwards.
Centripetal acceleration= (angular velocity)^2* radius.
Angular velocity= 2*pi*f=> 39.4/s2and radius =1m
So centripetal acceleration = 39.4m/s2

Answer 2

Explanation:

It is given that,

An object in uniform circular motion at the end of a 1 m rope, r = 1 m

Angular velocity of the object, $\omega=1\ rev/s=6.28\ rad/s$

Let a is the centripetal acceleration of an object. Its formula is given by :

$a=r\times \omega^2$

$a=1\times (6.28)^2$    

$a=39.43\ m/s^2$

So, the centripetal acceleration of an object in uniform circular motion $39.43\ m/s^2$. The direction of centripetal acceleration is inward. Hence, this is the required solution.