Question

what is cofficent of x if the expansion of (x+2)^3​

Answer 1

Answer:

The coefficient of x² is -6.

Step-by-step explanation:

The given expression is

(x-2)^3(x−2)

3

Using the formula:

(a-b)^3=a^3-3a^2b+3ab^2-b^3(a−b)

3

=a

3

−3a

2

b+3ab

2

−b

3

We get

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-(2^3)(x−2)

3

=x

3

−3(x

2

)(2)+3(x)(2

2

)−(2

3

)

(x-2)^3=x^3-6x^2+12x-8(x−2)

3

=x

3

−6x

2

+12x−8

Therefore, the coefficient of x² is -6.

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