what is complementary angle of (10x-88)?
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Answered by
1
Let the complementary angle of (10x - 88 ) = y
90 - 10x - 88 = y
2 - 10x = y
90 - 10x - 88 = y
2 - 10x = y
Sneha3123:
hey your answer is wrong
Answered by
1
let the compliment angle= y
(10x-88)+y=90°
10x-88+y=90°
10x+y=90°+88°
10x+y=178°
y=178°-10x
(10x-88)+y=90°
10x-88+y=90°
10x+y=90°+88°
10x+y=178°
y=178°-10x
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