Question

what is de brogle wavelength of alpha paticle accelerated through potential v​

Answer 1

ANSWER

Since the kinetic energy will be equal to the work done on particle,

K=qV

Also, p=

2mK

Thus, λ=

p

h

=

2mK

h

=

2mqV

h

For both to have same λ,

m

p

q

p

V=m

a

q

a

V

a

V

a

=

(4)(2)

1

V=

8

V

Answer is option A.

Answer By

avatar

Toppr