Question

What is de-broglie wavelength associated with an electron accelerated through a potential of 100V.

Answer 1

Answer:

1.227 Angstrom

Explanation:

for an electron

$wavelength = \frac{12.27}{ \sqrt{v} }$

so for V=100volts

wavelength =

$\frac{12.27}{ \sqrt{100} } = \frac{12.27}{10} = 1.227$

if u want the answer in metres, multiply it by

${10}^{ - 10}$