Question

What is Delta.S for the reaction N2(g) +O2(g) Right arrow. 2NO? Use Delta.G = 173.3 kJ at 303.0 K and Delta.H = 180.7 kJ. Use Delta.G = Delta.H – TDelta.S. 7.4 J/K 7.4 kJ/K 24.42 kJ/K 24.42 J/K

Answer 1

$\Delta S$ for the reaction $N_2(g)+O_2(g)\rightarrow 2NO(g)$ is +7.4kJ/K

Explanation:

According to Gibb's equation:

$\Delta G=\Delta H-T\Delta S$

$\Delta G$ = Gibbs free energy  = 173.3 kJ

$\Delta H$ = enthalpy change  = +180.7  kJ/mol

$\Delta S$ = entropy change  = ?

T = temperature = 303.0 K

Putting in the values :

$173.3=180.7-303.0\times \Delta S$

$\Delta S=7.4kJ/K$

Thus $\Delta S$ for the reaction $N_2(g)+O_2(g)\rightarrow 2NO(g)$ is +7.4 kJ/K

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Answer 2

Answer:

its b 7.4kj/K

Explanation: