Question

What is derivation of 3rd Equation of motion

Answer 1

OA = u

BC = v

OC = t (height)

Displacement = area of trapezium

s = 1/2×h × (P1 × P2)

=1/2 ×OC × (OA + BC)

=1/2× t × (u + v)............(1)

using

a = v - u/t

t =(v -u)/a .........(2)

from (1) & (2)

s = 1/2 ×( v - u) /a × (v+u)

s = v^2 - u^2 /2as

2as = v^2 - u^2