Math, asked by salman64, 1 year ago

what is differnt between S.I and c.I on RS 6000 at the rate 10 per for 3 yrs

Answers

Answered by duragpalsingh

Hey there! ☺☻☺

Given,
Principal = ₹ 6000
Rate = 10%
Time = 3 years

We know,
S.I = PRT/100
= 6000 × 10 × 3/100
= 60 × 10 × 3
= ₹ 1800

Now,
A = P (1+r/100)ⁿ
= 6000 (1+10/100)³
= 6000 × 11/10 × 11/10 × 11/10
= 6 × 1331
= ₹ 7986
C.I = A - P
= 7986 - 6000
= ₹ 1986
Now,
Difference b/w their S.I and C.I = 1986 - 1800
= ₹ 186
Hope It Helps You! ☺☻☺

biluminous: first and foremost, compound interest is always higher than simple interest in any condition as much as i know. second, your calculations for compound interest is wrong although the formula is wright.

duragpalsingh: Opps! I wrote 11^3 as 11^2. Thanks for informing!

biluminous: still you are forgetting to subtract the principal money in that formula of CI. your formula gives (principal money + interest) together

biluminous: see my solution or formula.

duragpalsingh: yeah

Answered by biluminous

P = 6000 Rs.

R = 10%

T = 3 years

S.I. = P*R*T/100

= 6000*10*3/100

= 1800 Rs.

C.I. = P*(1 + R/100)^T - P

= 6000*(1 + 10/100)^3 - 6000

= 6000*(1.331 - 1)

= 6000*(0.331)

= 1986 Rs.

C.I. - S.I. = 1986 - 1800

= 186 Rs. answer

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