Physics, asked by Anonymous, 3 months ago

what is dimension of A in a given equation were
F=Av
we're f is force ,v is velocity and a ks aceration?

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Answered by nusrathcassim

0

Answer:

F= Ava

$MLT^{-2} = A .LT^{-2} . LT^{-1} \\\\\frac{MLT^{-2}}{.L^{2} T^{-3}} = A\\\\A= ML^{-1} T^{1}$

Explanation:

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