What is energy stored in condenser if capacity 3mF and across P.D. 400V ?
Answers
Answer:
Correct option is B)
Since the capacitors are connected in series so charge flowing through them will be same.
Energy stored in first capacitor of capacitance 0.3μF is given by
E
1
=
2C
1
Q
2
E
1
=
2×0.3
Q
2
Energy stored in second capacitor of capacitance 0.6μF is given by
E
2
=
2C
2
Q
2
E
2
=
2×0.6
Q
2
Now ratio of energy stored by the condensers is given by
E
2
E
1
=
1
2
Solve any question of Electrostatic Potential and Capacitance with:-
The energy stored in the condenser of capacitance 3 nF is found to be 6 × 10⁻⁷ J.
Given :
Capacitance (C) = 3 nF = 3×10⁻⁹ F
Potential Difference = 400 V
To Find :
Energy stored in the condenser
Solution :
Magnetic field:
A magnetic field of currents is a heading field in the neighbourhood of a bait, energetic current, or changeful electric field at which point attractive forces are apparent.
A magnetic field of currents is presented by exciting energetic charges and inborn attractive moments of basic atoms guide a fundamental quantity feature famous as spin.
Magnetic field and energetic field are two together pertain and are components of the electromagnetic force, individual of the four fundamental forces of type.Magnetic field substance is likewise magnetic field of currents force or attractive force.
It is represented as heading H and is outlined as the percentage of the MMF wanted to generate the Flux Density (B) inside the material for one length of that material. Magnetic field force is calculated in parts of amperes/music.
Energy stored in a charged condenser can be given as -
Energy (E) =
where, C = Capacitance; V = Potential difference
∴ Energy stored in the condenser (E)
Therefore, the energy stored in the condenser of capacitance 3 nF is found to be 6 × 10⁻⁷ J.
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