Question

What is (f−g)(x)? f(x)=3x5+6x2−5 g(x)=2x4+7x2−x+16

Answer 1

here is ur answer buddy....,

3x^5 + 6x²-5 - (2x⁴+7x²-x+16)
=>3x^5 + 6x²-5-2x⁴-7x²+x-16

=>3x^5 - 2x² - x² + x -21

hope it helps

Answer 2

Answer:

$(f-g)(x)=3x^5-2x^4-x^2+x-21)$

Step-by-step explanation:

Given :  Functions $f(x)=3x^5+6x^2-5\\\\ g(x)=2x^4+7x^2-x+16$

We have to find (f-g)(x).

Consider the given functions

$f(x)=3x^5+6x^2-5\\\\ g(x)=2x^4+7x^2-x+16$

$(f-g)(x)=f(x)-g(x)$

We have,

$(f-g)(x)=3x^5+6x^2-5-(2x^4+7x^2-x+16)$

Simplify, we have,

$(f-g)(x)=3x^5+6x^2-5-2x^4-7x^2+x-16$

$(f-g)(x)=3x^5-2x^4-x^2+x-21$

Thus, $(f-g)(x)=3x^5-2x^4-x^2+x-21$