Question

What is f(x) = 2x2 + 28x – 5 written in vertex form?

Answer 1

first of all we have to find vertex . if any quadratic equation is in the form of ax² + bx + c , then vertex = -b/2a

here f(x) = 2x² + 28x - 5
compare it with ax² + bx + c
a =2 , b = 28 and c = -5
then, vertex = -28/2 × 2 = -7

now, coverts equation like f(x) = (x - vertex)² + Constant

so, f(x) = 2x² + 28x - 5
= 2x² + 28x + 98 - 103
=2(x² + 14x + 49) - 103
= 2(x + 7)² - 103

now, you can see it is like f(x) = (x - vertex)² + Constant.

hence,f(x) = (x + 7)² - 103 is in vertex form.

Answer 2

Answer:

the answer is B

Step-by-step explanation:

because i just took the test on edginuity thats the explination