Question

What is filled in a right cylindrical tank with base radius 14cm such that water level is 3cm below the top. when an iron ball is dropped in the tank, 3003cm3 of water flown out. find the radius of the ball. ​

Answer 1

Refer to the attached file.

:)

Answer 2

Answer:

10.5 cm

Step-by-step explanation:

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by the given conditions

We know that the water is 3cm down the cylindrical tank hence when the iron ball is dropped the water came out by also crossing the volume of 3 cm along with 3003cu.cm of water.

There volume of empty Cylinder tank =pi×r^2×h

=3.14×196×3

=1848.

Therefore ...the volume of iron ball = the volume of empty tank + the volume of water came out= 1848+3003=4851cu.cm

Therefore volume of iron ball=4/3×pi×r^3

4851 =4/3×22/7×r^3

4851×3×7/4×22= r^3

1157.625 = r^3

Therefore r= 10.5 cm

Hope you understand

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