Question

what is focal length of a lens used to correct the defect . when the far distance of myopia person is 100cm​

Answer 1

Answer:

The focal length of the lens for correcting distant vision =+0.667m. Thefar point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem? The nature of lens required to see the distant objects clearly is convexlens is power -

Answer 2

The focal length of the lens is 100 cm.

Explanation:

It is given that,

For a myopic eye, the object is placed at the infinity. Image is formed at the distance of 100 cm or 1 m.

$u=-\infty$

v = -100 cm

Let f is the focal length of the eye. Using lens formula as :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{f}=\dfrac{1}{(-100)}-\dfrac{1}{\infty}$

f = -100 cm

So, the focal length of the lens is 100 cm. Hence, this is the required solution.

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